Topic 1 of 7
Linear equations, inequalities, and absolute value
Step 11 · Algebra 1 topics
Solve multi-step linear equations and rearrange formulas, solve inequalities and compound inequalities, and solve equations and inequalities with absolute value.
Solving linear equations
Solving a linear equation means finding the value that makes it true. Simplify each side, gather the variable on one side, then undo the operations. A formula can be solved for one of its letters in the same way.
Example: Fractions and parentheses
Solve .
- Multiply both sides by 3: 2(x − 6) = 3x − 21.
- So 2x − 12 = 3x − 21.
- Subtract 2x and add 21: x = 9.
Answerx = 9
Example: Decimals
Solve 0.4x + 1.2 = 0.1x + 3.
- Multiply every term by 10: 4x + 12 = x + 30.
- 3x = 18, so x = 6.
Answerx = 6
Example: Solving a formula
Solve P = 2l + 2w for w.
- Subtract 2l from both sides: P − 2l = 2w.
- Divide both sides by 2.
Answer
Solving inequalities
Inequalities are solved like equations, except that multiplying or dividing by a negative number reverses the sign. A compound inequality joins two: "and" means both must hold, "or" means at least one must.
Example: Reversing the sign
Solve 5 − 3x ≥ 17.
- Subtract 5: −3x ≥ 12.
- Divide by −3 and reverse the sign: x ≤ −4.
Answerx ≤ −4
Example: A compound inequality
Solve −3 < 2x + 1 ≤ 9.
- Subtract 1 from all three parts: −4 < 2x ≤ 8.
- Divide by 2: −2 < x ≤ 4.
Answer−2 < x ≤ 4
Absolute value equations
|x| is the distance of x from 0, so it is never negative. |x| = 5 has two solutions, 5 and −5: both are 5 away from 0.
Example: An absolute value equation
Solve |x − 3| = 7.
- x − 3 is 7 or −7.
- So x = 10 or x = −4.
Answerx = 10 or x = −4
Example: Get it alone first
Solve 2|x + 1| − 4 = 6.
- Add 4: 2|x + 1| = 10.
- Divide by 2: |x + 1| = 5.
- x + 1 = 5 or x + 1 = −5.
Answerx = 4 or x = −6
Example: An absolute value inequality
Solve |x| < 3.
- The numbers less than 3 away from 0.
Answer−3 < x < 3
Try it yourself
Work each one on paper first, then open the answer to check.
Solve 3(x − 4) = 2x + 1.
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x = 13
Solve for h.
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Solve −2x + 5 < 11.
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x > −3
Solve 1 ≤ 3x − 2 < 10.
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1 ≤ x < 4
Solve |x + 2| = 9.
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x = 7 or x = −11
Solve |2x − 1| = 5.
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x = 3 or x = −2
Solve |x − 4| ≤ 2.
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2 ≤ x ≤ 6