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Topic 4 of 8

Step 14 · Trigonometry and precalculus topics

Know the restricted ranges that make sine, cosine and tangent invertible, evaluate inverse trig functions and compositions, and use them to find angles.

Restricted ranges

Sine is not one-to-one: many angles share each sine. To build an inverse, we keep only part of it, where each value appears exactly once.

FunctionInputsOutputs (angles)
sin⁡−1x\sin^{-1} x−1 ≤ x ≤ 1−π2≤y≤π2-\frac{\pi}{2} \le y \le \frac{\pi}{2}
cos⁡−1x\cos^{-1} x−1 ≤ x ≤ 10≤y≤π0 \le y \le \pi
tan⁡−1x\tan^{-1} xall real numbers−π2<y<π2-\frac{\pi}{2} < y < \frac{\pi}{2}
y = sin⁻¹x: inputs from −1 to 1, outputs from −π/2 to π/2 (about −1.57 to 1.57).

Evaluating inverses

To evaluate an inverse, ask which angle in the allowed range has that value.

Example: Inverse sine

Find sin⁡−112\sin^{-1}\frac{1}{2} and sin⁡−1(−1)\sin^{-1}(-1).

  1. sin⁡π6=12\sin\frac{\pi}{6} = \frac{1}{2}, and π6\frac{\pi}{6} is in the range.
  2. sin⁡(−π2)=−1\sin\left(-\frac{\pi}{2}\right) = -1.

Answerπ6\frac{\pi}{6} and −π2-\frac{\pi}{2}

Example: Inverse cosine

Find cos⁡−1(−22)\cos^{-1}\left(-\frac{\sqrt{2}}{2}\right).

  1. Cosine is negative in quadrant II.
  2. cos⁡3π4=−22\cos\frac{3\pi}{4} = -\frac{\sqrt{2}}{2}, and 3π4\frac{3\pi}{4} is between 0 and π.

Answer3π4\frac{3\pi}{4}

Example: A composition

Find sin⁡(cos⁡−135)\sin\left(\cos^{-1}\frac{3}{5}\right).

  1. Let θ = cos⁡−135\cos^{-1}\frac{3}{5}: a right triangle with adjacent side 3 and hypotenuse 5.
  2. The opposite side is 4.

Answer45\frac{4}{5}

Using inverses to find angles

Inverse trig functions turn side lengths into angles.

Example: An angle from sides

A ramp rises 1.2 m over a horizontal run of 8 m. What angle does it make with the ground?

  1. tan θ = 1.2 ÷ 8 = 0.15.
  2. θ = tan⁻¹(0.15), about 8.5°.

AnswerAbout 8.5°

Example: Every solution

Solve sin x = 0.4 for 0 ≤ x < 2π.

  1. sin⁻¹(0.4) gives one answer, about 0.412.
  2. The other is π − 0.412, about 2.730.

Answerx ≈ 0.412 or x ≈ 2.730

Example: A direction

A plane flies 300 km north and 400 km east. On what bearing (angle east of north) is it from its start?

  1. tan θ = 400 ÷ 300.
  2. θ = tan⁡−143\tan^{-1}\frac{4}{3}, about 53.1°.

AnswerAbout 53.1° east of north

Try it yourself

Work each one on paper first, then open the answer to check.

  1. Find sin⁡−132\sin^{-1}\frac{\sqrt{3}}{2}.

    Show answer

    π3\frac{\pi}{3}

  2. Find cos⁡−10\cos^{-1} 0.

    Show answer

    π2\frac{\pi}{2}

  3. Find tan⁡−1(−1)\tan^{-1}(-1).

    Show answer

    −π4-\frac{\pi}{4}

  4. Find cos⁡(sin⁡−1513)\cos\left(\sin^{-1}\frac{5}{13}\right).

    Show answer

    1213\frac{12}{13}

  5. What is sin⁡−1(sin⁡3π4)\sin^{-1}\left(\sin\frac{3\pi}{4}\right)?

    Show answer

    π4\frac{\pi}{4}

  6. A 20 ft ladder reaches 16 ft up a wall. What angle does it make with the ground?

    Show answer

    About 53.1°

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