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Topic 2 of 8

Step 13: Algebra 2

Polynomial functions and their roots

Step 13 · Algebra 2 topics

Read a polynomial's end behavior from its degree and leading coefficient, connect its roots to its factors and its graph, and divide polynomials, using the remainder theorem.

Degree and end behavior

A polynomial function's degree is its highest power. The degree and the sign of the leading coefficient decide what the graph does at the far left and the far right.

DegreeLeading coefficientLeft endRight end
evenpositiveupup
evennegativedowndown
oddpositivedownup
oddnegativeupdown
y = x³ − 4x (odd degree, positive): it starts low on the left, ends high on the right, and crosses the x-axis at −2, 0 and 2.

Example: End behavior

Describe the ends of f(x) = −2x⁴ + x³ − 5.

  1. The degree, 4, is even, and the leading coefficient, −2, is negative.

AnswerBoth ends go down

Roots and factors

If r is a root, so that f(r) = 0, then x − r is a factor, and the other way round. The graph meets the x-axis at each real root.

Example: From factors to roots

What are the roots of f(x) = (x − 1)(x + 3)²?

  1. x − 1 = 0 gives 1.
  2. (x + 3)² = 0 gives −3, a double root.

Answer1, and −3 twice

Example: From roots to a polynomial

Write a polynomial with roots 2, −1 and 4.

  1. Each root r gives a factor x − r.

Answerf(x) = (x − 2)(x + 1)(x − 4)

The fundamental theorem of algebra says that a polynomial of degree n has exactly n roots, counting repeated roots and complex ones.

Dividing polynomials

Divide polynomials by long division, or by synthetic division when dividing by x − r. The remainder theorem says the remainder when f(x) is divided by x − r is f(r).

Synthetic division of x³ − 6x² + 11x − 6 by x − 1: the result row gives x² − 5x + 6, remainder 0.

Example: Synthetic division

Divide x³ − 6x² + 11x − 6 by x − 1.

  1. Bring down the 1. Multiply by r = 1 and add each time.
  2. 1 × 1 = 1, and −6 + 1 = −5. −5 × 1 = −5, and 11 − 5 = 6. 6 × 1 = 6, and −6 + 6 = 0.
  3. The quotient is x² − 5x + 6, with remainder 0.

Answerx² − 5x + 6

Example: Finishing the factoring

Factor x³ − 6x² + 11x − 6 completely.

  1. From the division: (x − 1)(x² − 5x + 6).
  2. x² − 5x + 6 = (x − 2)(x − 3).

Answer(x − 1)(x − 2)(x − 3)

Example: The remainder theorem

Find the remainder when f(x) = x³ + 2x − 5 is divided by x − 2.

  1. f(2) = 8 + 4 − 5 = 7.

Answer7

Try it yourself

Work each one on paper first, then open the answer to check.

  1. Describe the ends of f(x) = 3x⁵ − x².

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    Down on the left, up on the right.

  2. At most how many turning points can a degree-4 polynomial have?

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    3

  3. What are the roots of (x + 2)(x − 5)²?

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    −2, and 5 twice

  4. Write a polynomial with roots 0, 3 and −3.

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    x(x − 3)(x + 3), which is x³ − 9x

  5. Divide x² + 5x + 6 by x + 2.

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    x + 3

  6. What is the remainder when x³ − 4x + 1 is divided by x − 3?

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    16

  7. Is x − 2 a factor of x³ − 8?

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    Yes: 2³ − 8 = 0.

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