Topic 3 of 8
Linear equations in one variable
Step 10 · Pre-algebra topics
Solve linear equations with the variable on both sides, distribute and collect like terms first, clear fractions, and recognize equations with no solution or infinitely many.
Variables on both sides
When x appears on both sides, first gather the x terms on one side and the plain numbers on the other. Then solve as before.
Example: x on both sides
Solve 5x + 3 = 2x + 15.
- Subtract 2x from both sides: 3x + 3 = 15.
- Subtract 3: 3x = 12.
- Divide by 3: x = 4.
- Check: 5 × 4 + 3 = 23 and 2 × 4 + 15 = 23.
Answerx = 4
Example: Negative coefficients
Solve 7 − 2x = 3x − 8.
- Add 2x to both sides: 7 = 5x − 8.
- Add 8: 15 = 5x.
- Divide by 5: x = 3.
Answerx = 3
Distributing and collecting terms
Parentheses come off first, using the distributive property: a(b + c) = ab + ac. Then collect like terms: x terms together and plain numbers together.
Example: Distributing
Solve 3(x + 4) = 2(x − 1) + 19.
- Distribute: 3x + 12 = 2x − 2 + 19.
- Collect: 3x + 12 = 2x + 17.
- Subtract 2x, then 12: x = 5.
Answerx = 5
Example: A minus outside
Simplify 8 − 2(x − 3).
- −2 times x is −2x, and −2 times −3 is +6.
- So it is 8 − 2x + 6, which is 14 − 2x.
Answer14 − 2x
Example: Fractions
Solve .
- Multiply every term by 6: 3x + 2x = 60.
- 5x = 60, so x = 12.
Answerx = 12
One, none or infinitely many solutions
A linear equation usually has exactly one solution. But when the x terms cancel, two other things can happen.
| After simplifying | Example | Solutions |
|---|---|---|
| x = a number | 3x + 1 = 7 gives x = 2 | one |
| a false statement | 2x + 1 = 2x + 5 gives 1 = 5 | none |
| a true statement | 2(x + 3) = 2x + 6 gives 6 = 6 | infinitely many |
Example: No solution
Solve 4x − 3 = 4(x + 1).
- Distribute: 4x − 3 = 4x + 4.
- Subtract 4x: −3 = 4, which is false.
AnswerNo solution
Example: Every number works
Solve 3(2x − 1) = 6x − 3.
- Distribute: 6x − 3 = 6x − 3.
- The two sides are the same for every x.
AnswerInfinitely many solutions
Try it yourself
Work each one on paper first, then open the answer to check.
Solve 6x − 5 = 2x + 11.
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x = 4
Solve 9 − x = 2x + 3.
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x = 2
Solve 2(x + 5) = 3x − 4.
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x = 14
Simplify 10 − 3(x + 2).
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4 − 3x
Solve .
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x = 12
How many solutions does 5x + 2 = 5x − 7 have?
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None: it simplifies to 2 = −7.
How many solutions does 4(x − 1) = 4x − 4 have?
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Infinitely many: the two sides are the same.